Panjang AC adalah....
Jawaban:
Misal AB = x dan AC = y
[tex] \tan(30) = \frac{4}{x} \\ \\ \frac{ \sqrt{3} }{3} = \frac{4}{x} \\ \\ \sqrt{3}x = 12 \\ \\ x = \frac{12}{ \sqrt{3} } \\ \\ x = \frac{12}{ \sqrt{3} } \times \frac{ \sqrt{3} }{ \sqrt{3} } \\ \\ x = \frac{ \cancel{12} \sqrt{3} }{ \cancel{3}} = 4 \sqrt{3} [/tex]
Panjang AB 4√3 cm
[tex] \cos(30) = \frac{4 \sqrt{3} }{y} \\ \\ \frac{ \sqrt{3} }{2} = \frac{4 \sqrt{3} }{y} \\ \\ \sqrt{3} y = 8 \sqrt{3} \\ \\ y = \frac{8 \cancel{\sqrt{3}} }{ \cancel{\sqrt{3}} } = 8[/tex]
Panjang AC 8 cm
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